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Simplifying 2c3 + 16c2 + -18c = 0 Reorder the terms: -18c + 16c2 + 2c3 = 0 Solving -18c + 16c2 + 2c3 = 0 Solving for variable 'c'. Factor out the Greatest Common Factor (GCF), '2c'. 2c(-9 + 8c + c2) = 0 Factor a trinomial. 2c((-9 + -1c)(1 + -1c)) = 0 Ignore the factor 2.Subproblem 1
Set the factor 'c' equal to zero and attempt to solve: Simplifying c = 0 Solving c = 0 Move all terms containing c to the left, all other terms to the right. Simplifying c = 0Subproblem 2
Set the factor '(-9 + -1c)' equal to zero and attempt to solve: Simplifying -9 + -1c = 0 Solving -9 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '9' to each side of the equation. -9 + 9 + -1c = 0 + 9 Combine like terms: -9 + 9 = 0 0 + -1c = 0 + 9 -1c = 0 + 9 Combine like terms: 0 + 9 = 9 -1c = 9 Divide each side by '-1'. c = -9 Simplifying c = -9Subproblem 3
Set the factor '(1 + -1c)' equal to zero and attempt to solve: Simplifying 1 + -1c = 0 Solving 1 + -1c = 0 Move all terms containing c to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + -1c = 0 + -1 Combine like terms: 1 + -1 = 0 0 + -1c = 0 + -1 -1c = 0 + -1 Combine like terms: 0 + -1 = -1 -1c = -1 Divide each side by '-1'. c = 1 Simplifying c = 1Solution
c = {0, -9, 1}
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